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authorAnthony Wang2022-03-20 19:17:36 -0500
committerAnthony Wang2022-03-20 19:17:36 -0500
commit9fb756b80bbcf3e6c86213012cb0e62dca0db486 (patch)
tree575f7e1cdd69eb8bc07f25bfb050b64e3f37a054
parent43a8e25e4e803794fbded027621210fe761314cc (diff)
1604F
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diff --git a/codeforces.md b/codeforces.md
index 756d117..be243bb 100644
--- a/codeforces.md
+++ b/codeforces.md
@@ -549,3 +549,5 @@
- 1632D: Wow at least I can still solve 2000 rating problems, since it's this difficulty, you can assume it has a reasonably easy and greedy solution, and then some binary search or two pointers to speed things up
- ~~1650G: Mostly BFS but the overcounting is very tricky to avoid, but you can think about what the longer paths look like to find a way to only count them once, basically when they diverge from the short paths~~
+
+- 1604F: Don't use binary search because it's cancerous to code, loop over every power of two instead which is much easier