mathematics_in_lean

My solutions for this book

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import Mathlib.Data.Nat.Prime
import Mathlib.Algebra.BigOperators.Order
import Mathlib.Tactic
import Mathlib.Tactic.IntervalCases

open BigOperators

theorem two_le {m : } (h0 : m  0) (h1 : m  1) : 2  m := by
  cases m; contradiction
  case succ m =>
    cases m; contradiction
    repeat' apply Nat.succ_le_succ
    apply zero_le

example {m : } (h0 : m  0) (h1 : m  1) : 2  m := by
  by_contra h
  push_neg at h
  interval_cases m <;> contradiction

example {m : } (h0 : m  0) (h1 : m  1) : 2  m := by
  by_contra h
  push_neg at h
  revert h0 h1
  revert h m
  decide

theorem exists_prime_factor {n : Nat} (h : 2  n) :  p : Nat, p.Prime  p  n := by
  by_cases np : n.Prime
  · use n, np
  induction' n using Nat.strong_induction_on with n ih
  dsimp at ih
  rw [Nat.prime_def_lt] at np
  push_neg  at np
  rcases np h with m, mltn, mdvdn, mne1
  have : m  0 := by
    intro mz
    rw [mz, zero_dvd_iff] at mdvdn
    linarith
  have mgt2 : 2  m := two_le this mne1
  by_cases mp : m.Prime
  · use m, mp
    exact mdvdn
  . rcases ih m mltn mgt2 mp with p, pp, pdvd
    use p, pp
    apply pdvd.trans mdvdn

theorem primes_infinite :  n,  p > n, Nat.Prime p := by
  intro n
  have : 2  Nat.factorial (n + 1) + 1 := by
    sorry,
  rcases exists_prime_factor this with p, pp, pdvd
  refine' p, _, pp
  show p > n
  by_contra ple
  push_neg  at ple
  have : p  Nat.factorial (n + 1) := by
    sorry,
  have : p  1 := by
    sorry,
  show False
  sorry
open Finset

section

variable {α : Type _} [DecidableEq α] (r s t : Finset α)

example : r  (s  t)  r  s  r  t := by
  rw [subset_iff]
  intro x
  rw [mem_inter, mem_union, mem_union, mem_inter, mem_inter]
  tauto

example : r  (s  t)  r  s  r  t := by
  simp [subset_iff]
  intro x
  tauto

example : r  s  r  t  r  (s  t) := by
  simp [subset_iff]
  intro x
  tauto

example : r  s  r  t = r  (s  t) := by
  ext x
  simp
  tauto

end

section

variable {α : Type _} [DecidableEq α] (r s t : Finset α)

example : (r  s)  (r  t) = r  s  t := by
  sorry
example : (r \ s) \ t = r \ (s  t) := by
  sorry
end

example (s : Finset ) (n : ) (h : n  s) : n   i in s, i :=
  Finset.dvd_prod_of_mem _ h

theorem Nat.Prime.eq_of_dvd_of_prime {p q : } (prime_p : Nat.Prime p) (prime_q : Nat.Prime q)
    (h : p  q) : p = q := by
  sorry
theorem mem_of_dvd_prod_primes {s : Finset } {p : } (prime_p : p.Prime) :
    ( n  s, Nat.Prime n)  (p   n in s, n)  p  s := by
  intro h₀ h₁
  induction' s using Finset.induction_on with a s ans ih
  · simp at h₁
    linarith [prime_p.two_le]
  simp [Finset.prod_insert ans, prime_p.dvd_mul] at h₀ h₁
  rw [mem_insert]
    sorry
example (s : Finset ) (x : ) : x  s.filter Nat.Prime  x  s  x.Prime :=
  mem_filter

theorem primes_infinite' :  s : Finset Nat,  p, Nat.Prime p  p  s := by
  intro s
  by_contra h
  push_neg  at h
  set s' := s.filter Nat.Prime with s'_def
  have mem_s' :  {n : }, n  s'  n.Prime := by
    intro n
    simp [s'_def]
    apply h
  have : 2  ( i in s', i) + 1 := by
    sorry,
  rcases exists_prime_factor this with p, pp, pdvd
  have : p   i in s', i := by
    sorry,
  have : p  1 := by
    convert Nat.dvd_sub' pdvd this
    simp
  show False
  sorry
theorem bounded_of_ex_finset (Q :   Prop) :
    ( s : Finset ,  k, Q k  k  s)   n,  k, Q k  k < n := by
  rintro s, hs
  use s.sup id + 1
  intro k Qk
  apply Nat.lt_succ_of_le
  show id k  s.sup id
  apply le_sup (hs k Qk)

theorem ex_finset_of_bounded (Q :   Prop) [DecidablePred Q] :
    ( n,  k, Q k  k  n)   s : Finset ,  k, Q k  k  s := by
  rintro n, hn
  use (range (n + 1)).filter Q
  intro k
  simp [Nat.lt_succ_iff]
  exact hn k

example : 27 % 4 = 3 := by norm_num

example (n : ) : (4 * n + 3) % 4 = 3 := by
  rw [add_comm, Nat.add_mul_mod_self_left]
  norm_num

theorem mod_4_eq_3_or_mod_4_eq_3 {m n : } (h : m * n % 4 = 3) : m % 4 = 3  n % 4 = 3 := by
  revert h
  rw [Nat.mul_mod]
  have : m % 4 < 4 := Nat.mod_lt m (by norm_num)
  interval_cases hm : m % 4 <;> simp [hm]
  have : n % 4 < 4 := Nat.mod_lt n (by norm_num)
  interval_cases hn : n % 4 <;> simp [hn]

theorem two_le_of_mod_4_eq_3 {n : } (h : n % 4 = 3) : 2  n := by
  apply two_le <;>
    · intro neq
      rw [neq] at h
      norm_num at h

theorem aux {m n : } (h₀ : m  n) (h₁ : 2  m) (h₂ : m < n) : n / m  n  n / m < n := by
  sorry
theorem exists_prime_factor_mod_4_eq_3 {n : Nat} (h : n % 4 = 3) :
     p : Nat, p.Prime  p  n  p % 4 = 3 := by
  by_cases np : n.Prime
  · use n
    exact np, dvd_rfl, h
  induction' n using Nat.strong_induction_on with n ih
  dsimp at ih
  rw [Nat.prime_def_lt] at np
  push_neg  at np
  rcases np (two_le_of_mod_4_eq_3 h) with m, mltn, mdvdn, mne1
  have mge2 : 2  m := by
    apply two_le _ mne1
    intro mz
    rw [mz, zero_dvd_iff] at mdvdn
    linarith
  have neq : m * (n / m) = n := Nat.mul_div_cancel' mdvdn
  have : m % 4 = 3  n / m % 4 = 3 := by
    apply mod_4_eq_3_or_mod_4_eq_3
    rw [neq, h]
  cases' this with h1 h1
    . sorry
    sorry
example (m n : ) (s : Finset ) (h : m  erase s n) : m  n  m  s := by
  rwa [mem_erase] at h

example (m n : ) (s : Finset ) (h : m  erase s n) : m  n  m  s := by
  simp at h
  assumption

theorem primes_mod_4_eq_3_infinite :  n,  p > n, Nat.Prime p  p % 4 = 3 := by
  by_contra h
  push_neg  at h
  cases' h with n hn
  have :  s : Finset Nat,  p : , p.Prime  p % 4 = 3  p  s := by
    apply ex_finset_of_bounded
    use n
    contrapose! hn
    rcases hn with p, pp, p4, pltn
    exact p, pltn, pp, p4
  cases' this with s hs
  have h₁ : ((4 *  i in erase s 3, i) + 3) % 4 = 3 := by
    sorry,
  rcases exists_prime_factor_mod_4_eq_3 h₁ with p, pp, pdvd, p4eq
  have ps : p  s := by
    sorry,
  have pne3 : p  3 := by
    sorry,
  have : p  4 *  i in erase s 3, i := by
    sorry,
  have : p  3 := by
    sorry,
  have : p = 3 := by
    sorry,
  contradiction