mathematics_in_lean

My solutions for this book

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import Mathlib.Analysis.SpecialFunctions.Log.Basic
import Mathlib.Tactic

variable (a b c d e : )
open Real

#check (le_refl :  a : , a  a)
#check (le_trans : a  b  b  c  a  c)

section
variable (h : a  b) (h' : b  c)

#check (le_refl :  a : Real, a  a)
#check (le_refl a : a  a)
#check (le_trans : a  b  b  c  a  c)
#check (le_trans h : b  c  a  c)
#check (le_trans h h' : a  c)

end

example (x y z : ) (h₀ : x  y) (h₁ : y  z) : x  z := by
  apply le_trans
  · apply h₀
  . apply h₁

example (x y z : ) (h₀ : x  y) (h₁ : y  z) : x  z := by
  apply le_trans h₀
  apply h₁

example (x y z : ) (h₀ : x  y) (h₁ : y  z) : x  z :=
  le_trans h₀ h₁

example (x : ) : x  x := by
  apply le_refl

example (x : ) : x  x :=
  le_refl x

#check (le_refl :  a, a  a)
#check (le_trans : a  b  b  c  a  c)
#check (lt_of_le_of_lt : a  b  b < c  a < c)
#check (lt_of_lt_of_le : a < b  b  c  a < c)
#check (lt_trans : a < b  b < c  a < c)

-- Try this.
example (h₀ : a  b) (h₁ : b < c) (h₂ : c  d) (h₃ : d < e) : a < e := by
  sorry

example (h₀ : a  b) (h₁ : b < c) (h₂ : c  d) (h₃ : d < e) : a < e := by
  linarith

section

example (h : 2 * a  3 * b) (h' : 1  a) (h'' : d = 2) : d + a  5 * b := by
  linarith

end

example (h : 1  a) (h' : b  c) : 2 + a + exp b  3 * a + exp c := by
  linarith [exp_le_exp.mpr h']

#check (exp_le_exp : exp a  exp b  a  b)
#check (exp_lt_exp : exp a < exp b  a < b)
#check (log_le_log : 0 < a  0 < b  (log a  log b  a  b))
#check (log_lt_log : 0 < a  a < b  log a < log b)
#check (add_le_add : a  b  c  d  a + c  b + d)
#check (add_le_add_left : a  b   c, c + a  c + b)
#check (add_le_add_right : a  b   c, a + c  b + c)
#check (add_lt_add_of_le_of_lt : a  b  c < d  a + c < b + d)
#check (add_lt_add_of_lt_of_le : a < b  c  d  a + c < b + d)
#check (add_lt_add_left : a < b   c, c + a < c + b)
#check (add_lt_add_right : a < b   c, a + c < b + c)
#check (add_nonneg : 0  a  0  b  0  a + b)
#check (add_pos : 0 < a  0 < b  0 < a + b)
#check (add_pos_of_pos_of_nonneg : 0 < a  0  b  0 < a + b)
#check (exp_pos :  a, 0 < exp a)
#check add_le_add_left

example (h : a  b) : exp a  exp b := by
  rw [exp_le_exp]
  exact h

example (h₀ : a  b) (h₁ : c < d) : a + exp c + e < b + exp d + e := by
  apply add_lt_add_of_lt_of_le
  · apply add_lt_add_of_le_of_lt h₀
    apply exp_lt_exp.mpr h₁
  apply le_refl

example (h₀ : d  e) : c + exp (a + d)  c + exp (a + e) := by sorry

example : (0 : ) < 1 := by norm_num

example (h : a  b) : log (1 + exp a)  log (1 + exp b) := by
  have h₀ : 0 < 1 + exp a := by sorry
  have h₁ : 0 < 1 + exp b := by sorry
  apply (log_le_log h₀ h₁).mpr
  sorry

example : 0  a ^ 2 := by
  -- apply?
  exact sq_nonneg a

example (h : a  b) : c - exp b  c - exp a := by
  sorry

example : 2 * a * b  a ^ 2 + b ^ 2 := by
  have h : 0  a ^ 2 - 2 * a * b + b ^ 2
  calc
    a ^ 2 - 2 * a * b + b ^ 2 = (a - b) ^ 2 := by ring
    _  0 := by apply pow_two_nonneg

  calc
    2 * a * b = 2 * a * b + 0 := by ring
    _  2 * a * b + (a ^ 2 - 2 * a * b + b ^ 2) :=
      add_le_add (le_refl _) h
    _ = a ^ 2 + b ^ 2 := by ring


example : 2 * a * b  a ^ 2 + b ^ 2 := by
  have h : 0  a ^ 2 - 2 * a * b + b ^ 2
  calc
    a ^ 2 - 2 * a * b + b ^ 2 = (a - b) ^ 2 := by ring
    _  0 := by apply pow_two_nonneg
  linarith

example : |a * b|  (a ^ 2 + b ^ 2) / 2 := by
  sorry

#check abs_le'.mpr