usaco

Clean implementations of solutions to USACO problems

  1. 1
  2. 2
  3. 3
  4. 4
  5. 5
  6. 6
  7. 7
  8. 8
  9. 9
  10. 10
  11. 11
  12. 12
  13. 13
  14. 14
  15. 15
  16. 16
  17. 17
  18. 18
  19. 19
  20. 20
  21. 21
  22. 22
  23. 23
  24. 24
  25. 25
  26. 26
  27. 27
  28. 28
  29. 29
  30. 30
  31. 31
  32. 32
  33. 33
  34. 34
  35. 35
  36. 36
  37. 37
  38. 38
  39. 39
  40. 40
  41. 41
  42. 42
  43. 43
  44. 44
  45. 45
  46. 46
  47. 47
  48. 48
  49. 49
  50. 50
  51. 51
  52. 52
  53. 53
  54. 54
  55. 55
  56. 56
  57. 57
  58. 58
  59. 59
  60. 60
  61. 61
  62. 62
  63. 63
  64. 64
  65. 65
  66. 66
  67. 67
  68. 68
  69. 69
  70. 70
  71. 71
  72. 72
  73. 73
  74. 74
  75. 75
  76. 76
  77. 77
  78. 78
  79. 79
  80. 80
  81. 81
  82. 82
  83. 83
  84. 84
  85. 85
  86. 86
  87. 87
  88. 88
  89. 89
  90. 90
  91. 91
  92. 92
  93. 93
  94. 94
  95. 95
  96. 96
  97. 97
  98. 98
  99. 99
#include <algorithm>
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <cmath>
#include <cstring>
#define init_io(pname) ifstream cin((string)pname+".in"); ofstream cout((string)pname+".out"); ios_base::sync_with_stdio(false); cin.tie(NULL)
#define FOR(i, a, b, in) for (int i = (a); i < (b); i += in)
#define REP(i, a, b) for (int i = (a); i < (b); i++)
#define RFOR(i, a, b, in) for (int i = (a) - 1; i >= (b); i -= in)
#define RREP(i, a, b) for (int i = (a) - 1; i >= (b); i--)
#define trav(a, x) for (auto& a : x)
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
#define rsz resize
#define mem(a, b) memset(a, (b), sizeof(a))
using namespace std;
typedef string str;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii; typedef pair<ll, ll> pl; typedef pair<ld, ld> pd;
typedef vector<int> vi; typedef vector<ll> vl; typedef vector<ld> vd;
typedef vector<ii> vii; typedef vector<pl> vpl; typedef vector<pd> vpd;
constexpr auto INF = (int)1e9;
constexpr auto LINF = (ll)1e18;

int N, A[100005];
vi ans;
pl seg[4 * 100005];

pl merge(const pl& a, const pl& b) {
	pl ret;
	if (a.first == b.first) ret = pl(a.first, (a.second + b.second < 0 ? LINF : a.second + b.second));
	else ret = (a.first > b.first ? a : b);
	return ret;
}

void update(int i, pl v, int l = 1, int r = -1, int n = 1) {
	if (r == -1) r = N;
	if (l == r) seg[n] = v;
	else {
		int m = (l + r) >> 1;
		i <= m ? update(i, v, l, m, n << 1) : update(i, v, m + 1, r, n << 1 | 1);
		seg[n] = merge(seg[n << 1], seg[n << 1 | 1]);
	}
}

pl query(int a, int b, int l = 1, int r = -1, int n = 1) {
	if (r == -1) r = N;
	if (l > b || r < a) return pl(0, 0);
	if (l >= a && r <= b) return seg[n];
	int m = (l + r) >> 1;
	return merge(query(a, b, l, m, n << 1), query(a, b, m + 1, r, n << 1 | 1));
}

int main() {
	init_io("itout");

	ll K;
	cin >> N >> K;
	for (int i = 0; i < N; i++) cin >> A[i];

	for (int i = 0; i < 4 * N; i++) seg[i] = pl(0, 0);

	for (int i = N - 1; i >= 0; i--) {
		pl q = query(A[i], N);
		if (q.first++ == 0) q.second++;
		update(A[i], q);
	}

	int d = query(1, N).first;
	cout << N - d << endl;
	for (int i = 0; i < N; i++) {
		pl q = query(A[i], A[i]);
		if (q.first == d) {
			if (K <= q.second) d--;
			else {
				ans.push_back(A[i]);
				K -= q.second;
			}
		}
		else ans.push_back(A[i]);
	}

	sort(ans.begin(), ans.end());
	for (auto& x : ans) cout << x << endl;
}