Create newbarn_naive.cpp

1 files changed, 72 insertions, 0 deletions

diff --git a/2018/February/Platinum/newbarn_naive.cpp b/2018/February/Platinum/newbarn_naive.cpp
new file mode 100644
index 0000000..86a3cd5
--- /dev/null
+++ b/2018/February/Platinum/newbarn_naive.cpp
@@ -0,0 +1,72 @@
+#include <algorithm>
+#include <iostream>
+#include <fstream>
+#include <string>
+#include <vector>
+#include <queue>
+#include <set>
+#include <map>
+#include <unordered_set>
+#include <unordered_map>
+#include <cmath>
+#include <cstring>
+#define init_io(pname) ifstream cin((string)pname+".in"); ofstream cout((string)pname+".out"); ios_base::sync_with_stdio(false); cin.tie(NULL)
+#define FOR(i, a, b, in) for (int i = (a); i < (b); i += in)
+#define REP(i, a, b) for (int i = (a); i < (b); i++)
+#define RFOR(i, a, b, in) for (int i = (a) - 1; i >= (b); i -= in)
+#define RREP(i, a, b) for (int i = (a) - 1; i >= (b); i--)
+#define trav(a, x) for (auto& a : x)
+#define mp make_pair
+#define pb push_back
+#define f first
+#define s second
+#define lb lower_bound
+#define ub upper_bound
+#define sz(x) (int)x.size()
+#define all(x) begin(x), end(x)
+#define rsz resize
+#define mem(a, b) memset(a, (b), sizeof(a))
+using namespace std;
+typedef string str;
+typedef long long ll;
+typedef long double ld;
+typedef pair<int, int> ii; typedef pair<ll, ll> pl; typedef pair<ld, ld> pd;
+typedef vector<int> vi; typedef vector<ll> vl; typedef vector<ld> vd;
+typedef vector<ii> vii; typedef vector<pl> vpl; typedef vector<pd> vpd;
+constexpr auto INF = (int)1e9;
+constexpr auto LINF = (ll)1e18;
+
+// Although this algorithm is O(n^2)
+// It can solve 8 / 10 test cases
+// It is also easy to code
+int P[100005], A[100005], B[100005];
+
+int main() {
+	init_io("newbarn");
+
+	int Q;
+	cin >> Q;
+	int u = 0;
+	while (Q--) {
+		char c;
+		cin >> c;
+		if (c == 'B') {
+			cin >> P[++u];
+			A[u] = B[u] = 0;
+			for (int v = u, h = 1; P[v] != -1 && B[P[v]] < h; v = P[v], h++) {
+				if (A[P[v]] < h) A[P[v]] = h;
+				else { B[P[v]] = h; break; }
+			}
+		}
+		else {
+			int k;
+			cin >> k;
+			int ans = A[k];
+			for (int v = k, h = 1; P[v] != -1; v = P[v], h++) {
+				if (A[P[v]] == A[v] + 1) ans = max(B[P[v]] + h, ans);
+				else ans = max(A[P[v]] + h, ans);
+			}
+			cout << ans << '\n';
+		}
+	}
+}